# Problem

In Python, a string of text can be aligned left, right and center.

.ljust(width)

```>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------
```

.center(width)

This method returns a centered string of length width.

```>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----
```

.rjust(width)

This method returns a right aligned string of length width.

```>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank
```

You are given a partial code that is used for generating the HackerRank Logo of variable thickness.

Your task is to replace the blank (______) with rjust, ljust or center.

#### Input Format

A single line containing the thickness value for the logo.

#### Constraints

The thickness must be an odd number.

#### Output Format

Output the desired logo.

```5
```

#### Sample Output

```   H
HHH
HHHHH
HHHHHHH
HHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHH
HHHHHHH
HHHHH
HHH
H
```

### Solution

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24``` ```#Replace all ______ with rjust, ljust or center. thickness = int(input()) #This must be an odd number c = 'H' #Top Cone for i in range(thickness): print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)) #Top Pillars for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)) #Middle Belt for i in range((thickness+1)//2): print((c*thickness*5).center(thickness*6)) #Bottom Pillars for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)) #Bottom Cone for i in range(thickness): print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)) ```
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