# Text Allignment in Python - HackerRank Solution

# Problem

In Python, a string of text can be aligned left, right and center.

.ljust(width)

```
>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------
```

.center(width)

This method returns a centered string of length width.

```
>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----
```

.rjust(width)

This method returns a right aligned string of length width.

```
>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank
```

#### Task

You are given a partial code that is used for generating the HackerRank Logo of variable thickness.

Your task is to replace the blank (______) with rjust, ljust or center.

Input Format

A single line containing the thickness value for the logo.

Constraints

The thickness must be an odd number.

Output Format

Output the desired logo.

Sample Input

```
5
```

Sample Output

H HHH HHHHH HHHHHHH HHHHHHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHHHHHHHHHHHHHHHHHHHHHH HHHHHHHHHHHHHHHHHHHHHHHHH HHHHHHHHHHHHHHHHHHHHHHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHH HHHHHHHHH HHHHHHH HHHHH HHH H

Solution

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #Replace all ______ with rjust, ljust or center. thickness = int(input()) #This must be an odd number c = 'H' #Top Cone for i in range(thickness): print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)) #Top Pillars for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)) #Middle Belt for i in range((thickness+1)//2): print((c*thickness*5).center(thickness*6)) #Bottom Pillars for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)) #Bottom Cone for i in range(thickness): print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)) |