# Problem

Therefore, Angle ABC = 90.
Point M is the midpoint of hypotenuse AC.
You are given the lengths AB and BC.
Your task is to find angle MBC (angle theta, as shown in the figure) in degrees.

#### Input Format

The first line contains the length of side AB.
The second line contains the length of side BC.

#### Constraints

Lengths AB and BC are natural numbers.

#### Output Format

Output angel MBC in degrees.

Note: Round the angle to the nearest integer.

#### Examples:

If angle is 56.5000001°, then output 57°.
If angle is 56.5000000°, then output 57°.
If angle is 56.4999999°, then output 56°.

```10
10
```

`45°`

### Solution

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16``` ```import math AB = int(input()) BC = int(input()) hypotenuse = math.sqrt(AB**2 + BC**2) hypotenuse = hypotenuse /2.0 adj = BC/2.0 output = int(round(math.degrees(math.acos(adj/hypotenuse )))) output = str(output) print(output+u'\N{DEGREE SIGN}') # Find Angle MBC in python - HackerRank Solution - docodehere.com ```

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