Python Program for cube sum of first n natural numbers

In this article, we will learn to find the sum of the cube of the first n number using the python program.

the sum of the cube of n numbers:

1³ + 2³ + 3³ + 4³ + ....... + (n-1)³ + n³

We find the sum of the cube of positive numbers from 1 to nth using two method

• using for loop
• using mathematically

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Method 1: Using for loop

Program

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# Sum of the cube of positive numbers from 1 to nth using forloop
n = int(input("Enter nth number: "))
sum = 0

for i in range(1,n+1):
    sum = sum + (i*i*i)

print("Sum of the cube of the number from 1 to",n,"is: ",sum)

# Sum of the cube of positive numbers from of nth using forloop - docodehere.com

Output

Enter nth number: 10
Sum of the cube of the number from 1 to 10 is:  3025

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Method 2: Using Mathematical formula

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# Sum of the cube of positive numbers from 1 to nth without forloop
n = int(input("Enter nth number: "))

print(( n * (n + 1) / 2 ) ** 2)

# Sum of the cube of positive numbers from of nth without forloop - docodehere.com

Enter nth number: 3
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