# Python Program for sum of squares of n natural numbers

In this article, we will learn to find the sum of the square of the first n number using the python program.

We find the sum of the square of positive numbers from 1 to nth using two methods:

- using for loop
- using mathematical formula

the sum of the square of n numbers:

1^{2} + 2^{2} + 3^{2} + 4^{2} + ....... + (n-1)^{2} + n^{2}

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Method 1: Using for loop

**O(N)**

#### Program

1 2 3 4 5 6 7 8 9 10 | # Sum of the square of positive numbers from 1 to nth using forloop n = int(input("Enter nth number: ")) sum = 0 for i in range(1,n+1): sum = sum + (i*i) print("Sum of the square of the number from 1 to",n,"is: ",sum) # Sum of the square of positive numbers from of nth using forloop - docodehere.com |

#### Output

Enter nth number: 10 Sum of the square of the number from 1 to 10 is: 385

Method 2: Using Mathematical formula

**O(1)**

#### Program

1 2 3 4 5 6 | # Sum of the square of positive numbers from 1 to nth without forloop n = int(input("Enter nth number: ")) print((n * (n + 1) / 2) * (2 * n + 1) / 3) # Sum of the square of positive numbers from of nth without forloop - docodehere.com |

#### Output

Enter nth number: 2 5